Integrand size = 22, antiderivative size = 51 \[ \int \frac {1}{\sqrt {3-2 x} \sqrt {1-3 x+x^2}} \, dx=-\frac {2 \sqrt {-1+3 x-x^2} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt {3-2 x}}{\sqrt [4]{5}}\right ),-1\right )}{\sqrt [4]{5} \sqrt {1-3 x+x^2}} \]
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Time = 0.02 (sec) , antiderivative size = 51, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.136, Rules used = {705, 703, 227} \[ \int \frac {1}{\sqrt {3-2 x} \sqrt {1-3 x+x^2}} \, dx=-\frac {2 \sqrt {-x^2+3 x-1} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt {3-2 x}}{\sqrt [4]{5}}\right ),-1\right )}{\sqrt [4]{5} \sqrt {x^2-3 x+1}} \]
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Rule 227
Rule 703
Rule 705
Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt {-1+3 x-x^2} \int \frac {1}{\sqrt {3-2 x} \sqrt {-\frac {1}{5}+\frac {3 x}{5}-\frac {x^2}{5}}} \, dx}{\sqrt {5} \sqrt {1-3 x+x^2}} \\ & = -\frac {\left (2 \sqrt {-1+3 x-x^2}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {1-\frac {x^4}{5}}} \, dx,x,\sqrt {3-2 x}\right )}{\sqrt {5} \sqrt {1-3 x+x^2}} \\ & = -\frac {2 \sqrt {-1+3 x-x^2} F\left (\left .\sin ^{-1}\left (\frac {\sqrt {3-2 x}}{\sqrt [4]{5}}\right )\right |-1\right )}{\sqrt [4]{5} \sqrt {1-3 x+x^2}} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 10.03 (sec) , antiderivative size = 63, normalized size of antiderivative = 1.24 \[ \int \frac {1}{\sqrt {3-2 x} \sqrt {1-3 x+x^2}} \, dx=-\frac {2 \sqrt {3-2 x} \sqrt {-1+3 x-x^2} \operatorname {Hypergeometric2F1}\left (\frac {1}{4},\frac {1}{2},\frac {5}{4},\frac {1}{5} (3-2 x)^2\right )}{\sqrt {5} \sqrt {1-3 x+x^2}} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(101\) vs. \(2(42)=84\).
Time = 2.45 (sec) , antiderivative size = 102, normalized size of antiderivative = 2.00
method | result | size |
default | \(\frac {\sqrt {3-2 x}\, \sqrt {x^{2}-3 x +1}\, \sqrt {\left (-2 x +3+\sqrt {5}\right ) \sqrt {5}}\, \sqrt {\left (-3+2 x \right ) \sqrt {5}}\, \sqrt {\left (2 x -3+\sqrt {5}\right ) \sqrt {5}}\, F\left (\frac {\sqrt {2}\, \sqrt {5}\, \sqrt {\left (-2 x +3+\sqrt {5}\right ) \sqrt {5}}}{10}, \sqrt {2}\right )}{10 x^{3}-45 x^{2}+55 x -15}\) | \(102\) |
elliptic | \(-\frac {2 \sqrt {-\left (-3+2 x \right ) \left (x^{2}-3 x +1\right )}\, \sqrt {-5 \left (x -\frac {3}{2}-\frac {\sqrt {5}}{2}\right ) \sqrt {5}}\, \sqrt {10}\, \sqrt {\left (x -\frac {3}{2}\right ) \sqrt {5}}\, \sqrt {\left (x -\frac {3}{2}+\frac {\sqrt {5}}{2}\right ) \sqrt {5}}\, F\left (\frac {\sqrt {-5 \left (x -\frac {3}{2}-\frac {\sqrt {5}}{2}\right ) \sqrt {5}}}{5}, \sqrt {2}\right )}{25 \sqrt {3-2 x}\, \sqrt {x^{2}-3 x +1}\, \sqrt {-2 x^{3}+9 x^{2}-11 x +3}}\) | \(116\) |
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.12 (sec) , antiderivative size = 11, normalized size of antiderivative = 0.22 \[ \int \frac {1}{\sqrt {3-2 x} \sqrt {1-3 x+x^2}} \, dx=-\sqrt {-2} {\rm weierstrassPInverse}\left (5, 0, x - \frac {3}{2}\right ) \]
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\[ \int \frac {1}{\sqrt {3-2 x} \sqrt {1-3 x+x^2}} \, dx=\int \frac {1}{\sqrt {3 - 2 x} \sqrt {x^{2} - 3 x + 1}}\, dx \]
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\[ \int \frac {1}{\sqrt {3-2 x} \sqrt {1-3 x+x^2}} \, dx=\int { \frac {1}{\sqrt {x^{2} - 3 \, x + 1} \sqrt {-2 \, x + 3}} \,d x } \]
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\[ \int \frac {1}{\sqrt {3-2 x} \sqrt {1-3 x+x^2}} \, dx=\int { \frac {1}{\sqrt {x^{2} - 3 \, x + 1} \sqrt {-2 \, x + 3}} \,d x } \]
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Timed out. \[ \int \frac {1}{\sqrt {3-2 x} \sqrt {1-3 x+x^2}} \, dx=\int \frac {1}{\sqrt {3-2\,x}\,\sqrt {x^2-3\,x+1}} \,d x \]
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